1.If ∫sec2xcosec4x dx=−13cot3x+ktanx−2cotx+C\int \sec^2 x \cosec^4 x\,dx = -\frac13\cot^3 x + k\tan x - 2\cot x + C∫sec2xcosec4xdx=−31cot3x+ktanx−2cotx+C, then k=k=k=a.4b.3c.2d.1Login to continueOnly logged in users canattempt or see the solution.
