1.If x2+y2+2kx+4y−4=0x^2+y^2+2kx+4y-4=0x2+y2+2kx+4y−4=0 has centre in 4th4^{th}4th quadrant and touches x2+y2+6x−2y+6=0x^2+y^2+6x-2y+6=0x2+y2+6x−2y+6=0, then k=k=k=a.−5-5−5b.−15/7-15/7−15/7c.−23/5-23/5−23/5d.−1-1−1Login to continueOnly logged in users canattempt or see the solution.
