1.If A=(0sinαsinα0)A = \begin{pmatrix} 0 & \sin\alpha \\ \sin\alpha & 0 \end{pmatrix}A=(0sinαsinα0) and det(A2−12I)=0\det\left(A^{2} - \dfrac{1}{2}I\right) = 0det(A2−21I)=0, then a possible value of α\alphaα is:a.π6\dfrac{\pi}{6}6πb.π3\dfrac{\pi}{3}3πc.π4\dfrac{\pi}{4}4πd.π2\dfrac{\pi}{2}2πLogin to continueOnly logged in users canattempt or see the solution.
