1.Area bounded by y=sec−1xy = \sec^{-1} xy=sec−1x, y=cot−1xy = \cot^{-1} xy=cot−1x and line x=1x = 1x=1 is given by -a.∫11+52(cot−1x−sec−1x) dx\int_{1}^{\frac{1+\sqrt{5}}{2}} (\cot^{-1} x - \sec^{-1} x) \, dx∫121+5(cot−1x−sec−1x)dxb.∫0αsecx dx+∫απ/4cotx dx\int_{0}^{\alpha} \sec x \, dx + \int_{\alpha}^{\pi/4} \cot x \, dx∫0αsecxdx+∫απ/4cotxdx where sinα=cos2α\sin \alpha = \cos^2 \alphasinα=cos2αc.∫0αsecx dx+∫απ/4cotx dx−π4+1\int_{0}^{\alpha} \sec x \, dx + \int_{\alpha}^{\pi/4} \cot x \, dx - \frac{\pi}{4} + 1∫0αsecxdx+∫απ/4cotxdx−4π+1 where sinα=cos2α\sin \alpha = \cos^2 \alphasinα=cos2αd.∫11+52(cot−1x−sec−1x) dx\int_{1}^{\frac{1+\sqrt{5}}{2}} (\cot^{-1} x - \sec^{-1} x) \, dx∫121+5(cot−1x−sec−1x)dxLogin to continueOnly logged in users canattempt or see the solution.
