1.Find out the compounds that will disproportionate in their aqueous solution.(I) ClO4−→+0.36VClO3−→+0.33VClO2→+0.66VOCl−→+0.40V12Cl2→+1.36VCl−\text{ClO}_4^- \xrightarrow{+0.36\text{V}} \text{ClO}_3^- \xrightarrow{+0.33\text{V}} \text{ClO}_2 \xrightarrow{+0.66\text{V}} \text{OCl}^- \xrightarrow{+0.40\text{V}} \frac{1}{2}\text{Cl}_2 \xrightarrow{+1.36\text{V}} \text{Cl}^-ClO4−+0.36VClO3−+0.33VClO2+0.66VOCl−+0.40V21Cl2+1.36VCl−(II) MnO4−→+0.56VMnO42−→+2.22VMnO2→+0.95VMn3+→+1.55VMn2+→−0.19VMn\text{MnO}_4^- \xrightarrow{+0.56\text{V}} \text{MnO}_4^{2-} \xrightarrow{+2.22\text{V}} \text{MnO}_2 \xrightarrow{+0.95\text{V}} \text{Mn}^{3+} \xrightarrow{+1.55\text{V}} \text{Mn}^{2+} \xrightarrow{-0.19\text{V}} \text{Mn}MnO4−+0.56VMnO42−+2.22VMnO2+0.95VMn3++1.55VMn2+−0.19VMna.(I) ClO2\text{ClO}_2ClO2, Cl2\text{Cl}_2Cl2(II) MnO42−\text{MnO}_4^{2-}MnO42−, Mn3+\text{Mn}^{3+}Mn3+b.(I) ClO3−\text{ClO}_3^-ClO3−, OCl−\text{OCl}^-OCl−(II) MnO2\text{MnO}_2MnO2, Mn2+\text{Mn}^{2+}Mn2+c.(I) OCl−\text{OCl}^-OCl− only(II) MnO2\text{MnO}_2MnO2, Mn2+\text{Mn}^{2+}Mn2+d.(I) ClO3−\text{ClO}_3^-ClO3− only(II) MnO2\text{MnO}_2MnO2 onlyLogin to continueOnly logged in users canattempt or see the solution.