1.Let ppp and qqq be real numbers such that p≠0p \neq 0p=0, p3≠qp^3 \neq qp3=q and p3≠−qp^3 \neq -qp3=−q. If α\alphaα and β\betaβ are non-zero complex numbers satisfying α+β=−p\alpha+\beta=-pα+β=−p and α3+β3=q\alpha^3+\beta^3=qα3+β3=q, then a quadratic equation having α/β\alpha/\betaα/β and β/α\beta/\alphaβ/α as its roots isa.(p3+q)x2−(p3+2q)x+(p3+q)=0(p^3+q)x^2 - (p^3+2q)x + (p^3+q) = 0(p3+q)x2−(p3+2q)x+(p3+q)=0b.(p3+q)x2−(p3−2q)x+(p3+q)=0(p^3+q)x^2 - (p^3-2q)x + (p^3+q) = 0(p3+q)x2−(p3−2q)x+(p3+q)=0c.(p3−q)x2−(5p3−2q)x+(p3−q)=0(p^3-q)x^2 - (5p^3-2q)x + (p^3-q) = 0(p3−q)x2−(5p3−2q)x+(p3−q)=0d.(p3−q)x2−(5p3+2q)x+(p3−q)=0(p^3-q)x^2 - (5p^3+2q)x + (p^3-q) = 0(p3−q)x2−(5p3+2q)x+(p3−q)=0Login to continueOnly logged in users canattempt or see the solution.