The combustion of benzene ($l$) gives $CO_2(g)$ and $H_2O(l)$. Given that heat of combustion of benzene at constant volume is $-3263.9$ kJ mol$^{-1}$ at $25^\circ$C; the heat of combustion (in kJ mol$^{-1}$) of benzene at constant pressure will be ($R = 8.314$ JK$^{-1}$ mol$^{-1}$)