1.If ω\omegaω is the complex cube root of unity, then (3+5ω+3ω2)2+(3+3ω+5ω2)2=\left(3+5\omega+3\omega^2\right)^2 + \left(3+3\omega+5\omega^2\right)^2 =(3+5ω+3ω2)2+(3+3ω+5ω2)2=a.−1-1−1b.000c.444d.−4-4−4Login to continueOnly logged in users canattempt or see the solution.