1.The system of equationskx+y+z=1,x+ky+z=k,x+y+kz=k2kx + y + z = 1,\quad x + ky + z = k,\quad x + y + kz = k^2kx+y+z=1,x+ky+z=k,x+y+kz=k2has no solution if kkk is equal to:a.0b.1c.-1d.-2Login to continueOnly logged in users canattempt or see the solution.