1.Let α,β\alpha, \betaα,β be two roots of the quadratic equation x2+ax−b=0x^2 + ax - b = 0x2+ax−b=0, b≠0b \neq 0b=0. If the straight line xcosθ+ysinθ=cx\cos\theta + y\sin\theta = cxcosθ+ysinθ=c touches the curve (x/α)n+(y/β)n=2(x/\alpha)^n + (y/\beta)^n = 2(x/α)n+(y/β)n=2 at the point (α,β)(\alpha, \beta)(α,β), then (a/b)2+2/b(a/b)^2 + 2/b(a/b)2+2/b is equal toa.12c2\frac{1}{2c^2}2c21b.4c2\frac{4}{c^2}c24c.2c2\frac{2}{c^2}c22d.1c2\frac{1}{c^2}c21Login to continueOnly logged in users canattempt or see the solution.
