1.A projectile is launched at t=0t=0t=0 with velocity uuu at angle θ\thetaθ with the horizontal. The ratio of the rate of change of speed to the radius of curvature at the point of projection isa.2g2sinθcosθu2\dfrac{2 g^2 \sin\theta \cos\theta}{u^2}u22g2sinθcosθb.2g2sinθu2\dfrac{2 g^2 \sin\theta}{u^2}u22g2sinθc.g2sinθu2\dfrac{g^2 \sin\theta}{u^2}u2g2sinθd.g2sinθcosθu2\dfrac{g^2 \sin\theta \cos\theta}{u^2}u2g2sinθcosθLogin to continueOnly logged in users canattempt or see the solution.