1.If f(x)=∣2cosx10π2−x2cosx1012cosx∣f(x) = \begin{vmatrix} 2\cos x & 1 & 0 \\ \frac{\pi}{2} - x & 2\cos x & 1 \\ 0 & 1 & 2\cos x \end{vmatrix}f(x)=2cosx2π−x012cosx1012cosx, then f′(π)f'(\pi)f′(π) is equal toa.000b.222c.π\piπd.π−6\pi - 6π−6Login to continueOnly logged in users canattempt or see the solution.
