1.Let AAA be a 3×33\times 33×3 matrix and ∣A∣=2|A| = 2∣A∣=2. If ∣adj(adj(⋯(adj A)⋯ ))∣=2n\left|\text{adj}\bigl(\text{adj}(\cdots(\text{adj}\,A)\cdots)\bigr)\right| = 2^{n}adj(adj(⋯(adjA)⋯))=2n, where the adjoint is applied 202420242024 times, then the remainder when 2n2^{n}2n is divided by 999 is equal to:a.777b.444c.111d.000Login to continueOnly logged in users canattempt or see the solution.