1.
Let AA be a 3×33\times 3 matrix and A=2|A| = 2. If adj(adj((adjA)))=2n\left|\text{adj}\bigl(\text{adj}(\cdots(\text{adj}\,A)\cdots)\bigr)\right| = 2^{n}, where the adjoint is applied 20242024 times, then the remainder when 2n2^{n} is divided by 99 is equal to: