1.Let α,β\alpha, \betaα,β be the roots of the equation x2−2x−3=0x^2 - \sqrt{2} x - \sqrt{3} = 0x2−2x−3=0. Let Pn=αn−βnP_n = \alpha^n - \beta^nPn=αn−βn, n∈Nn \in \mathbb{N}n∈N. Then (113−102)P10+(112+10)P11−11P12(11\sqrt{3} - 10\sqrt{2}) P_{10} + (11\sqrt{2} + 10) P_{11} - 11 P_{12}(113−102)P10+(112+10)P11−11P12 is equal toa.103P910\sqrt{3} P_9103P9b.113P911\sqrt{3} P_9113P9c.102P910\sqrt{2} P_9102P9d.112P911\sqrt{2} P_9112P9Login to continueOnly logged in users canattempt or see the solution.
