1.Let α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R be such that the equation ax2−2bx+15=0ax^2 - 2bx + 15 = 0ax2−2bx+15=0 has a repeated root α\alphaα, and if α\alphaα and β\betaβ are the roots of the equation x2−2bx+21=0x^2 - 2bx + 21 = 0x2−2bx+21=0, then α2+β2\alpha^2 + \beta^2α2+β2 is equal to:a.373737b.585858c.686868d.929292Login to continueOnly logged in users canattempt or see the solution.
