1.If zzz satisfies the equation ∣z∣−z=1+2i|z| - z = 1 + 2i∣z∣−z=1+2i, then zzz is equal toa.32+2i\frac{3}{2} + 2i23+2ib.32−2i\frac{3}{2} - 2i23−2ic.2−32i2 - \frac{3}{2}i2−23id.2+32i2 + \frac{3}{2}i2+23iLogin to continueOnly logged in users canattempt or see the solution.
