1.p,qp,qp,q are eccentricities of x2/a2−y2/b2=1x^2/a^2-y^2/b^2=1x2/a2−y2/b2=1 and its conjugate. Area of square from intersection of x2/p2+y2/q2=1x^2/p^2+y^2/q^2=1x2/p2+y2/q2=1 and x2=y2x^2=y^2x2=y2 isa.444b.2\sqrt{2}2c.3/2\sqrt{3}/23/2d.161616Login to continueOnly logged in users canattempt or see the solution.