1.A certain number of spherical drops of a liquid of radius rrr coalesce to form a single drop of radius RRR and volume VVV. If TTT is the surface tension of the liquid then:a.Energy 4VT(1/r−1/R)4VT(1/r - 1/R)4VT(1/r−1/R) is releasedb.Energy =3VT(1/r+1/R)= 3VT(1/r + 1/R)=3VT(1/r+1/R) is releasedc.Energy =3VT(1/r−1/R)= 3VT(1/r - 1/R)=3VT(1/r−1/R) is releasedd.Energy is neither released nor absorbedLogin to continueOnly logged in users canattempt or see the solution.