1.CH3COOH→LiAlH4X→Cu,300∘CY→Dil. NaOHZ\text{CH}_3\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{X} \xrightarrow{\text{Cu}, 300^\circ\text{C}} \text{Y} \xrightarrow{\text{Dil. NaOH}} \text{Z}CH3COOHLiAlH4XCu,300∘CYDil. NaOHZIn the above reaction, Z is:a.Butanolb.Aldolc.Ketold.AcetalLogin to continueOnly logged in users canattempt or see the solution.
