1.∫−22(1+2sinx)e∣x∣ dx\int_{-2}^{2} (1 + 2\sin x) e^{|x|}\,dx∫−22(1+2sinx)e∣x∣dx is equal toa.000b.e2−1e^2-1e2−1c.2(e2−1)2(e^2-1)2(e2−1)d.111Login to continueOnly logged in users canattempt or see the solution.
