1.For θ∈(0,π/2)\theta \in (0,\pi/2)θ∈(0,π/2), the maximum value of sin(θ+π12)+cos(θ+π4)\sin\left(\theta+\dfrac{\pi}{12}\right) + \cos\left(\theta+\dfrac{\pi}{4}\right)sin(θ+12π)+cos(θ+4π) is attained at θ=\theta =θ=a.π12\dfrac{\pi}{12}12πb.π6\dfrac{\pi}{6}6πc.π4\dfrac{\pi}{4}4πd.π3\dfrac{\pi}{3}3πLogin to continueOnly logged in users canattempt or see the solution.
