1.If AAA is 3×33\times33×3 non-singular and ∣A∣=3|A|=3∣A∣=3, then ∣(2A)−1∣=|(2A)^{-1}| =∣(2A)−1∣=a.242424b.333c.13\frac{1}{3}31d.124\frac{1}{24}241Login to continueOnly logged in users canattempt or see the solution.
