1.If Re(z−12z+i)=1\operatorname{Re}\left(\dfrac{z - 1}{2z + i}\right) = 1Re(2z+iz−1)=1, where z=x+iyz = x + iyz=x+iy, then the point (x,y)(x, y)(x,y) lies on a:a.circle whose centre is at (−12,−32)\left(-\dfrac{1}{2}, -\dfrac{3}{2}\right)(−21,−23)b.straight line whose slope is −23-\dfrac{2}{3}−32c.straight line whose slope is 32\dfrac{3}{2}23d.circle whose diameter is 5\sqrt{5}5Login to continueOnly logged in users canattempt or see the solution.
