1.In an AC circuit, the instantaneous voltage and current are given by e(t)=5[cosωt+3sinωt]e(t) = 5[\cos\omega t + \sqrt{3}\sin\omega t]e(t)=5[cosωt+3sinωt] V and i(t)=5sin(ωt+π/4)i(t) = 5\sin(\omega t + \pi/4)i(t)=5sin(ωt+π/4) A respectively. Then:a.Current leads voltage by π4\dfrac{\pi}{4}4πb.Voltage leads current by π3\dfrac{\pi}{3}3πc.Voltage leads current by π4\dfrac{\pi}{4}4πd.Current leads voltage by π12\dfrac{\pi}{12}12πLogin to continueOnly logged in users canattempt or see the solution.
