1.The function f(x)={14(3x2+1),−∞<x≤15−4x,1<x<44−x,4≤x<∞f(x) = \begin{cases} \dfrac{1}{4}(3x^2 + 1), & -\infty < x \leq 1 \\[8pt] 5 - 4x, & 1 < x < 4 \\[8pt] 4 - x, & 4 \leq x < \infty \end{cases}f(x)=⎩⎨⎧41(3x2+1),5−4x,4−x,−∞<x≤11<x<44≤x<∞ is:a.continuous at x=1x = 1x=1 and x=4x = 4x=4b.continuous at x=1x = 1x=1, discontinuous at x=4x = 4x=4c.continuous at x=4x = 4x=4, discontinuous at x=1x = 1x=1d.discontinuous at x=1x = 1x=1 and x=4x = 4x=4Login to continueOnly logged in users canattempt or see the solution.
