1.The solution of dydx=cos(x+y)+sin(x+y)\frac{dy}{dx} = \cos(x + y) + \sin(x + y)dxdy=cos(x+y)+sin(x+y) isa.log[1+tan(x+y2)]+C=0\log\left[1 + \tan\left(\frac{x+y}{2}\right)\right] + C = 0log[1+tan(2x+y)]+C=0b.log[1+tan(x+y2)]=x+C\log\left[1 + \tan\left(\frac{x+y}{2}\right)\right] = x + Clog[1+tan(2x+y)]=x+Cc.log[1−tan(x+y2)]=x+C\log\left[1 - \tan\left(\frac{x+y}{2}\right)\right] = x + Clog[1−tan(2x+y)]=x+Cd.None of the aboveLogin to continueOnly logged in users canattempt or see the solution.
