1.If θ=cot−1(7)+cot−1(8)+cot−1(18)\theta = \cot^{-1}(7) + \cot^{-1}(8) + \cot^{-1}(18)θ=cot−1(7)+cot−1(8)+cot−1(18), then cotθ\cot \thetacotθ is equal toa.222b.333c.444d.111Login to continueOnly logged in users canattempt or see the solution.
