1.If y(x)y(x)y(x) is the solution of dydx+2x+1xy=e−2x\frac{dy}{dx} + \frac{2x+1}{x}y = e^{-2x}dxdy+x2x+1y=e−2x, x>0x>0x>0, where y(1)=12e−2y(1) = \frac{1}{2}e^{-2}y(1)=21e−2, thena.y(loge2)=loge4y(\log_e 2) = \log_e 4y(loge2)=loge4b.y(loge2)=loge24y(\log_e 2) = \frac{\log_e 2}{4}y(loge2)=4loge2c.y(x)y(x)y(x) is decreasing in (1/2,1)(1/2, 1)(1/2,1)d.y(x)y(x)y(x) is decreasing in (0,1)(0,1)(0,1)Login to continueOnly logged in users canattempt or see the solution.
