1.If z=x+iyz = x + iyz=x+iy is a complex number satisfying ∣z+i2∣2=∣z−i2∣2\left|z + \frac{i}{2}\right|^2 = \left|z - \frac{i}{2}\right|^2z+2i2=z−2i2, then the locus of zzz isa.x-axisb.y-axisc.y=xy = xy=xd.2y=x2y = x2y=xLogin to continueOnly logged in users canattempt or see the solution.
