1.limx→01+xsinx−cosxtan22x\displaystyle\lim_{x\to0}\frac{\sqrt{1+x}\sin x-\sqrt{\cos x}}{\tan^2 2x}x→0limtan22x1+xsinx−cosxa.333b.3/23/23/2c.3/43/43/4d.3/163/163/16Login to continueOnly logged in users canattempt or see the solution.