1.Let A=(02qrpq−rp−qr)\displaystyle A = \begin{pmatrix} 0 & 2q & r \\ p & q & -r \\ p & -q & r \end{pmatrix}A=0pp2qq−qr−rr. If AAT=I3A A^{T} = I_3AAT=I3, then ∣p∣|p|∣p∣ is equal to:a.12\dfrac{1}{\sqrt{2}}21b.15\dfrac{1}{\sqrt{5}}51c.16\dfrac{1}{\sqrt{6}}61d.13\dfrac{1}{\sqrt{3}}31Login to continueOnly logged in users canattempt or see the solution.
