1.If xsin3θ+ycos3θ=sinθcosθx \sin^3 \theta + y \cos^3 \theta = \sin \theta \cos \thetaxsin3θ+ycos3θ=sinθcosθ and xsinθ=ycosθx \sin \theta = y \cos \thetaxsinθ=ycosθ, then x2+y2=x^2 + y^2 =x2+y2=a.1b.2c.0d.None of theseLogin to continueOnly logged in users canattempt or see the solution.
