1.The differential equation for the family of curves y=csinxy = c \sin xy=csinx can be given bya.(dydx)2=y2cot2x\left(\frac{dy}{dx}\right)^2 = y^2 \cot^2 x(dxdy)2=y2cot2xb.(dydx)2−(secxdydx)2+y2=0\left(\frac{dy}{dx}\right)^2 - \left(\sec x \frac{dy}{dx}\right)^2 + y^2 = 0(dxdy)2−(secxdxdy)2+y2=0c.(dydx)2=tan2x\left(\frac{dy}{dx}\right)^2 = \tan^2 x(dxdy)2=tan2xd.dydx=ycotx\frac{dy}{dx} = y \cot xdxdy=ycotxLogin to continueOnly logged in users canattempt or see the solution.
