1.The expression Aˉ(A+B)+(B+AA)(A+Bˉ)\bar{A}(A + B) + (B + AA)(A + \bar{B})Aˉ(A+B)+(B+AA)(A+Bˉ) simplifies toa.A+BA + BA+Bb.ABABABc.A+BA + BA+Bd.Aˉ+Bˉ\bar{A} + \bar{B}Aˉ+BˉLogin to continueOnly logged in users canattempt or see the solution.
