1.If θ1\theta_1θ1 and θ2\theta_2θ2 be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip θ\thetaθ is given bya.cot2θ=cot2θ1+cot2θ2\cot^2\theta = \cot^2\theta_1 + \cot^2\theta_2cot2θ=cot2θ1+cot2θ2b.tan2θ=tan2θ1+tan2θ2\tan^2\theta = \tan^2\theta_1 + \tan^2\theta_2tan2θ=tan2θ1+tan2θ2c.cot2θ=cot2θ1−cot2θ2\cot^2\theta = \cot^2\theta_1 - \cot^2\theta_2cot2θ=cot2θ1−cot2θ2d.tan2θ=tan2θ1−tan2θ2\tan^2\theta = \tan^2\theta_1 - \tan^2\theta_2tan2θ=tan2θ1−tan2θ2Login to continueOnly logged in users canattempt or see the solution.