1.If x2+9y2−4x+3=0x^2 + 9y^2 - 4x + 3 = 0x2+9y2−4x+3=0, x,y∈Rx, y \in \mathbb{R}x,y∈R, then xxx and yyy respectively lie in the intervalsa.[13,1]\left[\frac{1}{3}, 1\right][31,1] and [13,1]\left[\frac{1}{3}, 1\right][31,1]b.[1,3]\left[1, 3\right][1,3] and [−13,13]\left[-\frac{1}{3}, \frac{1}{3}\right][−31,31]c.[13,1]\left[\frac{1}{3}, 1\right][31,1] and [1,3]\left[1, 3\right][1,3]d.[1,3]\left[1, 3\right][1,3] and [1,3]\left[1, 3\right][1,3]Login to continueOnly logged in users canattempt or see the solution.
